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Java’s String class encapsulates an array of bytes. A byte can be converted to a char, in which case, String becomes an array ...
// Time Complexity: O(n²) (due to substring creation and window reset) } else if (right == s.length() - 1 && !(map.containsKey(s ...
A simple solution is to one by one consider all substrings of first string and for every substring check if it is a substring in ...
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